4.9x^2+14x=80

Solution for 4.9x^2+14x=80 equation:

4.9x^2+14x=80

We move all terms to the left:

4.9x^2+14x-(80)=0

a = 4.9; b = 14; c = -80;
Δ = b2-4ac
Δ = 142-4·4.9·(-80)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-42}{2*4.9}=\frac{-56}{9.8}
=-5+7/9.8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+42}{2*4.9}=\frac{28}{9.8}
=2+6/7
$